Q: How do you write 56 as a product of prime numbers?

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56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

no

No because as a product of its prime factors: 2*2*2*7 = 56

No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56

As a product of its prime factors: 2*2*2*7 = 56

2x2x2x7

56 = 2 x 2x 2 x 7 56 = 23 x 7

As a product of its prime factors in exponents: 26*56 = 1,000,000

The prime numbers (factors) of 56 are: 2 and 7

The prime numbers (factors) of 56 are: 2 and 7

56 = 2 x 2 x 2 x 7

Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.

56=2x2x2x7

53 and 3 are two prime numbers that add up to 56

56 does not have only three prime factors.

The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.

56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.

56 = 2 x 2 x 2 x 7 = 23 x 7

None of those four numbers are prime numbers.

One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...

As a product of its prime factors: 2*3*7 = 42 As a product of its prime factors: 2*2*2*7 = 56

300

As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39

LVI = 56

As a product of its prime factors: 2*2*2*2 = 16 As a product of its prime factors: 2*2*2*7 = 56

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